What is the 10th term of the following arithmetic progression 2 7 12?

The 10th term of the arithmetic progression 2, 7, 12 is 47.

Here's how to find it:

An arithmetic progression (AP) is a sequence of numbers such that the difference between consecutive terms is constant. This constant difference is called the common difference (d).

• First term (a): In this AP, the first term (a) is 2.
• Common difference (d): The common difference (d) is the difference between any two consecutive terms. For instance, 7 - 2 = 5, and 12 - 7 = 5. So, d = 5.

The nth term of an AP can be found using the formula: a_n = a + (n-1)d.

To find the 10th term (a₁₀):

• n = 10
• a = 2
• d = 5

Substituting these values into the formula:

a₁₀ = 2 + (10 - 1) 5
a₁₀ = 2 + (9) 5
a₁₀ = 2 + 45
a₁₀ = 47

Therefore, the 10th term is 47, as stated in the reference which indicates: "Hence, 10th term is a+9d = 2+45 = 47. Was this answer helpful? Find the 10th term of the A.P. 2, 7, 12, ......."