What is the 30th term of the arithmetic progression 5 8 11 by using a suitable formula?

The 30th term of the arithmetic progression 5, 8, 11 is 92.

To find the 30th term of the arithmetic progression, we can use the formula:

T_n = a + (n - 1)d

Where:

• T_n is the nth term
• a is the first term
• n is the term number
• d is the common difference

In this case:

• a = 5
• n = 30
• d = 8 - 5 = 3

Calculation

Substituting these values into the formula, we get:

T₃₀ = 5 + (30 - 1) 3
T₃₀ = 5 + 29 3
T₃₀ = 5 + 87
T₃₀ = 92

As stated in the provided reference: ⇒ T₃₀ = 5 + 29 x 3. ⇒ T₃₀ = 5 + 87. ⇒ T₃₀ = 92. ∴ 30th terms of an ap T₃₀ = 92.

Therefore, the 30th term of the arithmetic progression is 92.