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How many 2-digit numbers are divisible by 4 in an arithmetic progression?

Published in Arithmetic Progressions 1 min read

There are 22 two-digit numbers divisible by 4, forming an arithmetic progression.

Here's how we determine that:

  • Identify the first 2-digit number divisible by 4: That's 12 (4 x 3).

  • Identify the last 2-digit number divisible by 4: That's 96 (4 x 24).

  • Recognize the arithmetic progression: The numbers divisible by 4 form an arithmetic progression with a common difference of 4: 12, 16, 20, ..., 96.

  • Use the arithmetic progression formula: To find the number of terms (n) in an arithmetic progression, we can use the formula:

    Last term = First term + (n - 1) * Common difference

    96 = 12 + (n - 1) 4
    84 = (n - 1)
    4
    21 = n - 1
    n = 22

Therefore, there are 22 two-digit numbers that are divisible by 4, which clearly follows an arithmetic progression since they are multiples of 4.

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