The nth term of the arithmetic progression (AP) is 4n + 3.
Here's how we arrive at this answer:
Deriving the nth Term
Given the sum of the first n terms, Sn = 2n2 + 5n, we can find the nth term (an) using the following logic:
- Sn represents the sum of the first n terms: a1 + a2 + ... + an.
- Sn-1 represents the sum of the first n-1 terms: a1 + a2 + ... + an-1.
- Therefore, the nth term (an) is the difference between Sn and Sn-1: an = Sn - Sn-1.
Calculation
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Find Sn-1:
Substitute n-1 for n in the expression for Sn:
Sn-1 = 2(n-1)2 + 5(n-1)
Sn-1 = 2(n2 - 2n + 1) + 5n - 5
Sn-1 = 2n2 - 4n + 2 + 5n - 5
Sn-1 = 2n2 + n - 3 -
Calculate an = Sn - Sn-1:
an = (2n2 + 5n) - (2n2 + n - 3)
an = 2n2 + 5n - 2n2 - n + 3
an = 4n + 3
Therefore, the nth term of the AP is 4n + 3.