What is the 10th term of an arithmetic progression 5 9 13?

The 10th term of the arithmetic progression 5, 9, 13 is 41.

To find the 10th term of an arithmetic progression, we can use the following formula:

a_n = a₁ + (n - 1)d

Where:

• a_n is the nth term we want to find.
• a₁ is the first term of the arithmetic progression.
• n is the term number we want to find.
• d is the common difference between consecutive terms.

In this case:

• a₁ = 5
• n = 10
• d = 9 - 5 = 4

Substituting these values into the formula:

a₁₀ = 5 + (10 - 1) 4
a₁₀ = 5 + (9) 4
a₁₀ = 5 + 36
a₁₀ = 41

Therefore, the 10th term of the arithmetic progression is indeed 41, as confirmed by a previous response stating, "hence the 10th term of the ap is 41...".