The sum of the first 10 terms of the arithmetic progression (AP) 15, 10, 5 is -75.
Understanding Arithmetic Progressions (AP)
An arithmetic progression is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant difference is called the common difference (d).
- First term (a): The first number in the sequence. In this case, a = 15.
- Common difference (d): The constant difference between consecutive terms. Here, d = 10 - 15 = -5.
- Number of terms (n): The number of terms in the sequence we want to sum. In this question, n = 10.
Calculating the Sum of an AP
The sum (Sn) of the first n terms of an arithmetic progression can be calculated using the formula:
Sn = (n/2) * [2a + (n-1)d]
Where:
- Sn is the sum of the first n terms.
- n is the number of terms.
- a is the first term.
- d is the common difference.
Applying the Formula to the Given AP
Let's plug in the values from the AP 15, 10, 5 into the formula:
- a = 15
- d = -5
- n = 10
S10 = (10/2) [2(15) + (10-1)(-5)]
S10 = 5 [30 + (9)(-5)]
S10 = 5 [30 - 45]
S10 = 5 [-15]
S10 = -75
Therefore, the sum of the first 10 terms of the AP 15, 10, 5 is -75, as confirmed by the reference.