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What is the formula for the kinetic energy of an electron in a Bohr orbit?

Published in Atomic Physics 2 mins read

The kinetic energy (KE) of an electron in a Bohr orbit is given by the magnitude of the total energy, but with a positive sign.

Here's a breakdown:

The total energy (E) of an electron in the nth Bohr orbit is given by:

E = - (Z2e4m) / (8ε02h2n2)

where:

  • Z is the atomic number (number of protons in the nucleus)
  • e is the elementary charge (magnitude of the electron's charge)
  • m is the mass of the electron
  • ε0 is the permittivity of free space
  • h is Planck's constant
  • n is the principal quantum number (orbit number)

According to the Virial Theorem, for a Coulomb potential (like the one between the electron and the nucleus), the kinetic energy is related to the potential energy (V) and total energy (E) by:

2KE + V = 0

Also, the total energy (E) is the sum of kinetic energy (KE) and potential energy (V):

E = KE + V

From these relationships we can say: V = 2E, and KE = -E.
Therefore, kinetic energy can be expressed as:

KE = (Z2e4m) / (8ε02h2n2)

It's important to note:

  • The kinetic energy is always a positive value.
  • The total energy is negative, indicating a bound state (the electron is bound to the nucleus).
  • As the principal quantum number (n) increases, the kinetic energy decreases, and the electron is less tightly bound to the nucleus.

In simpler terms: The kinetic energy of an electron in a Bohr orbit is equal to the magnitude of its total energy but expressed as a positive value.

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