To differentiate a function divided by another function, you use the quotient rule.
Here's how the quotient rule works:
If you have a function h(x) defined as:
h(x) = f(x) / g(x)
Then the derivative of h(x), denoted as h'(x), is given by:
h'(x) = [g(x) f'(x) - f(x) g'(x)] / [g(x)]2
Where:
- f'(x) is the derivative of f(x)
- g'(x) is the derivative of g(x)
Explanation and Breakdown:
The quotient rule is a fundamental rule in calculus used to find the derivative of a function that is the ratio of two other functions. It's essential for differentiating expressions where one function is divided by another.
Here's a step-by-step breakdown:
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Identify f(x) and g(x): Determine which function is in the numerator (f(x)) and which is in the denominator (g(x)).
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Find the derivatives f'(x) and g'(x): Calculate the derivatives of both the numerator and denominator functions. You may need to apply other differentiation rules (power rule, chain rule, etc.) to find these derivatives.
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Apply the formula: Substitute f(x), g(x), f'(x), and g'(x) into the quotient rule formula:
h'(x) = [g(x) f'(x) - f(x) g'(x)] / [g(x)]2
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Simplify: Simplify the resulting expression algebraically to obtain the final derivative h'(x).
Example:
Let's say h(x) = (x2 + 1) / (x - 2)
- f(x) = x2 + 1
- g(x) = x - 2
Now, find the derivatives:
- f'(x) = 2x
- g'(x) = 1
Apply the quotient rule:
h'(x) = [(x - 2) (2x) - (x2 + 1) (1)] / (x - 2)2
Simplify:
h'(x) = [2x2 - 4x - x2 - 1] / (x - 2)2
h'(x) = (x2 - 4x - 1) / (x - 2)2
Therefore, the derivative of h(x) = (x2 + 1) / (x - 2) is h'(x) = (x2 - 4x - 1) / (x - 2)2.
Key Takeaways:
- The quotient rule is crucial when dealing with functions that are the ratio of two other functions.
- Remember the order of operations in the numerator: (g(x) f'(x)) - (f(x) g'(x)). Switching the order will result in the wrong answer.
- Always simplify the final expression as much as possible.