To differentiate a quadratic equation, apply the power rule and constant multiple rule.
Let's clarify the process of differentiating a quadratic equation. A quadratic equation generally takes the form:
f(x) = ax2 + bx + c
Where a, b, and c are constants. To find the derivative, f'(x), we apply the power rule (d/dx (xn) = nxn-1) and the constant multiple rule (d/dx (cf(x)) = c d/dx f(x)). We also know the derivative of a constant is zero.
Here's how to do it step-by-step:
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Differentiate the first term (ax2):
- Apply the power rule: d/dx (x2) = 2x1 = 2x
- Apply the constant multiple rule: d/dx (ax2) = a * 2x = 2ax
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Differentiate the second term (bx):
- Remember that x is x1
- Apply the power rule: d/dx (x1) = 1x0 = 1 (since anything to the zero power equals 1 - from the reference material)
- Apply the constant multiple rule: d/dx (bx) = b * 1 = b
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Differentiate the third term (c):
- The derivative of a constant is zero: d/dx (c) = 0
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Combine the results:
f'(x) = 2ax + b + 0 = 2ax + b
Example:
Let's say we have the quadratic equation:
f(t) = -3t2 + 2t + 4
Following the steps:
- Derivative of -3t2 is -6t
- Derivative of 2t is 2
- Derivative of 4 is 0 (From the reference: "And the derivative of a constant is 4 simplifying I get - 6 T 1st + 2 remember t to the 0. Equals. 1")
Therefore:
f'(t) = -6t + 2