askvity

What is the Equation for Sulphur Dioxide Gas and Acidified Potassium Dichromate Solution?

Published in Chemical Equation Sulphur Dioxide Dichromate 3 mins read

The chemical equation for the reaction between sulphur dioxide gas and acidified potassium dichromate solution is:

K₂Cr₂O₇ + 2H₂SO₄ + 3SO₂ → Cr₂(SO₄)₃ + K₂SO₄ + 2H₂O

This reaction is a classic example of a redox reaction where dichromate acts as an oxidizing agent and sulphur dioxide acts as a reducing agent.

Understanding the Reaction Components

Let's break down the key players in this chemical process:

  • Reactants: The substances that react together.
    • Potassium Dichromate (K₂Cr₂O₇): An orange crystalline solid, often used as an oxidizing agent in various applications.
    • Sulphuric Acid (H₂SO₄): A strong acid used here to acidify the solution, providing the necessary hydrogen ions (H⁺) for the reaction to proceed effectively.
    • Sulphur Dioxide (SO₂): A pungent gas produced by the burning of sulfur-containing materials.
  • Products: The new substances formed by the reaction.
    • Chromium(III) Sulphate (Cr₂(SO₄)₃): A green solution containing chromium ions in the +3 oxidation state. This distinct color change from orange to green is a visual indicator that the reaction has occurred and chromium has been reduced.
    • Potassium Sulphate (K₂SO₄): A soluble salt.
    • Water (H₂O): A common product in many acid-base and redox reactions.

The Balanced Chemical Equation

As provided in the reference, the balanced equation representing this reaction is:

K₂Cr₂O₇(aq) + 2H₂SO₄(aq) + 3SO₂(g) → Cr₂(SO₄)₃(aq) + K₂SO₄(aq) + 2H₂O(l)

(Note: State symbols have been added for clarity: (aq) for aqueous solution, (g) for gas, (l) for liquid.)

Redox Chemistry Explained

In this reaction, chromium in potassium dichromate starts in the +6 oxidation state (Cr⁶⁺) and is reduced to the +3 oxidation state (Cr³⁺) in chromium(III) sulphate. Simultaneously, sulphur in sulphur dioxide starts in the +4 oxidation state (S⁴⁺) and is oxidized to the +6 oxidation state (S⁶⁺), typically ending up as sulphate ions (SO₄²⁻).

This electron transfer process is the core of the redox reaction. The colour change from the characteristic orange of dichromate ions to the green of chromium(III) ions is a key visual identifier of this specific redox reaction.

Summary Table

Component Formula Role Initial Colour (in solution) Final Colour (if changing)
Potassium Dichromate K₂Cr₂O₇ Oxidizing Agent Orange -
Sulphuric Acid H₂SO₄ Acidifier Colourless -
Sulphur Dioxide SO₂ Reducing Agent Colourless (gas) -
Chromium(III) Sulphate Cr₂(SO₄)₃ Product - Green
Potassium Sulphate K₂SO₄ Product Colourless -
Water H₂O Product Colourless -

This reaction is often used in qualitative analysis to test for the presence of sulphur dioxide gas, as the orange-to-green color change is quite dramatic and easily observable.

Related Articles