Balancing the chemical equation for the reaction of sodium with water, Na + H2O = NaOH + H2, requires adjusting the coefficients to ensure the number of atoms of each element is the same on both sides of the equation.
Here's how you balance the equation step-by-step:
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Start with the unbalanced equation:
Na + H2O → NaOH + H2 -
Count the atoms of each element on both sides:
- Left side (Reactants):
- Na: 1
- H: 2
- O: 1
- Right side (Products):
- Na: 1
- H: 3 (1 from NaOH + 2 from H2)
- O: 1
- Left side (Reactants):
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Balance hydrogen first. Since hydrogen appears as 2 on the left and 3 on the right, you'll need to find a common multiple. Place a coefficient of 2 in front of H2O on the left and a coefficient of 2 in front of NaOH on the right.
2 H2O + Na → 2 NaOH + H2 -
Recount the atoms:
- Left side (Reactants):
- Na: 1
- H: 4
- O: 2
- Right side (Products):
- Na: 1
- H: 4 (2 from 2NaOH + 2 from H2)
- O: 2
- Left side (Reactants):
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Balance sodium. Now sodium is no longer balanced. There is one on the left and two on the right. Place a 2 in front of Na on the left.
2Na + 2 H2O → 2 NaOH + H2 -
Final Check: Make sure the number of atoms for each element is the same on both sides.
- Left side: Na: 2, H: 4, O: 2
- Right side: Na: 2, H: 4, O: 2
The balanced chemical equation is: 2Na + 2H2O → 2NaOH + H2