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What is molar mass divided by empirical mass?

Published in Chemistry Formulas 3 mins read

The result of dividing molar mass by empirical mass is a whole number, or a value very close to a whole number. This ratio is used to determine the molecular formula of a compound.

Understanding Molar Mass and Empirical Mass

Before we delve into the result of this division, let's clarify the terms involved:

  • Molar Mass: The molar mass of a substance is the mass of one mole of that substance, typically measured in grams per mole (g/mol). It’s found by summing the atomic masses of all atoms in the molecular formula.
  • Empirical Mass: The empirical mass is the mass of one mole of the empirical formula of the compound. The empirical formula represents the simplest whole-number ratio of atoms in a compound.

Calculating the Ratio

The provided reference highlights that:

Divide the molar mass of the compound by the empirical formula mass. The result should be a whole number or very close to a whole number.

This whole number result has significance as it helps us determine the molecular formula using the empirical formula.

How It Works

  1. Determine the Empirical Formula: Obtain the simplest whole-number ratio of atoms in the compound.
  2. Calculate the Empirical Mass: Find the molar mass of the empirical formula.
  3. Calculate the Molar Mass: Calculate the actual molar mass of the compound (often given or experimentally determined).
  4. Divide Molar Mass by Empirical Mass: Divide the molar mass by the empirical mass to get a whole number or a value close to a whole number.
  5. Determine the Molecular Formula: Multiply all the subscripts in the empirical formula by the whole number obtained in step 4.

Example

Let's say you have a compound with an empirical formula of CH2O and a molar mass of 180 g/mol.

  1. Empirical Formula: CH2O
  2. Empirical Mass:
    • C: 12.01 g/mol
    • H: 2 x 1.01 g/mol = 2.02 g/mol
    • O: 16.00 g/mol
    • Total Empirical Mass = 12.01 + 2.02 + 16.00 = 30.03 g/mol
  3. Molar Mass: Given as 180 g/mol
  4. Divide: 180 g/mol / 30.03 g/mol ≈ 6
  5. Molecular Formula: Multiply the subscripts in CH2O by 6. Therefore the molecular formula is C6H12O6.

Practical Insights

  • This ratio is crucial for determining the molecular formula, which provides the actual number of each type of atom in a molecule.
  • The result is practically always a whole number, due to the nature of how molecules are formed and since the empirical formula is the simplest whole number ratio.
  • If you get a number far from a whole number, it suggests an error in either the empirical formula, the empirical mass, the molar mass calculation or experimental determination of the molar mass.

Summary

Step Description
1. Find Empirical Formula Mass Calculate the mass of one mole of the empirical formula.
2. Find Molar Mass Calculate the molar mass of the compound.
3. Divide Molar Mass by Empirical Mass The result is the factor to determine the molecular formula.

In essence, dividing the molar mass by the empirical mass yields a whole number that indicates how many times the empirical formula's mass is contained within the molecular formula's mass.

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