The integrating factor of a linear differential equation is a function that, when multiplied by the entire differential equation, makes it possible to integrate the equation directly.
Understanding Integrating Factors
The purpose of an integrating factor is to transform a non-exact differential equation into an exact one. This allows us to solve the differential equation using direct integration techniques. Integrating factors are most commonly used with first-order linear ordinary differential equations.
First-Order Linear Ordinary Differential Equations
A first-order linear ordinary differential equation can be written in the following standard form:
dy/dx + P(x)y = Q(x)
where P(x) and Q(x) are functions of x.
Calculating the Integrating Factor
The integrating factor, often denoted by μ(x) or IF, is calculated as follows:
μ(x) = e∫P(x) dx
Where:
e
is the base of the natural logarithm.∫P(x) dx
is the integral of the function P(x) with respect to x.
How to Use the Integrating Factor
- Identify P(x): Ensure your differential equation is in the standard form (dy/dx + P(x)y = Q(x)) and identify P(x).
- Calculate the Integrating Factor: Use the formula μ(x) = e∫P(x) dx to find the integrating factor.
- Multiply the Entire Equation: Multiply both sides of the original differential equation by the integrating factor μ(x). This results in: μ(x)dy/dx + μ(x)P(x)y = μ(x)Q(x). The left-hand side should now be the derivative of the product of y and the integrating factor [d/dx(yμ(x))].
- Integrate: Integrate both sides of the modified equation with respect to x. The left side will simplify to yμ(x). ∫ [d/dx(yμ(x))] dx = ∫ μ(x)Q(x) dx, therefore, yμ(x) = ∫ μ(x)Q(x) dx.
- Solve for y: Solve the resulting equation for y to obtain the general solution to the differential equation: y = [∫ μ(x)Q(x) dx] / μ(x)
Example
Let's say we have the differential equation:
dy/dx + (2/x)y = x
- Identify P(x): P(x) = 2/x
- Calculate the Integrating Factor: μ(x) = e∫(2/x) dx = e2ln|x| = eln(x2) = x2
- Multiply the Entire Equation: x2(dy/dx) + x2(2/x)y = x2(x) which simplifies to x2(dy/dx) + 2xy = x3
- Integrate: ∫[x2(dy/dx) + 2xy] dx = ∫x3 dx, which means x2y = (x4/4) + C
- Solve for y: y = (x2/4) + C/x2
Summary
The integrating factor is a crucial tool for solving first-order linear ordinary differential equations. It transforms a non-exact equation into an exact one, allowing direct integration and ultimately leading to the solution.