There are 100 numbers between 200 and 500 that are divisible by 3.
Here's how we arrive at that answer, leveraging the provided reference and some basic math:
First, let's find the first number greater than 200 that's divisible by 3. That number is 201 (since 201 / 3 = 67).
Next, let's find the last number less than 500 that's divisible by 3. That number is 498 (since 498 / 3 = 166).
Now, we have an arithmetic sequence: 201, 204, 207, ..., 498. The common difference is 3. To find the number of terms in this sequence (i.e., the number of multiples of 3), we use the formula:
Number of terms = (Last term - First term) / Common difference + 1
Number of terms = (498 - 201) / 3 + 1
Number of terms = 297 / 3 + 1
Number of terms = 99 + 1
Number of terms = 100
The reference supports this, stating, "In each 3 consecutive numbers, One number is divisible by number 3 and so the count is 301/3 = 100 and 1 is the remainder. As both the numbers 200 and 500 are not divisible by the number 3, The remainder is not increasing the count of numbers divisible by 3 and the answer is 100."
