There are 11 numbers between 101 and 200 that are divisible by 9.
Here's how we arrive at that answer, drawing upon the information in our reference:
The reference states that the first three-digit number between 100 and 200 divisible by 9 is 108, and the last is 198. This tells us the range we're working with, since the question is from 101 to 200.
It also states that the number of multiples of 9 between 100 and 200 can be found with the equation (198-99)/9 = 99/9 = 11
- Finding the First Multiple: The smallest number after 101 that's divisible by 9 is 108. (101 / 9 = 11 with a remainder; 12 * 9 = 108).
- Finding the Last Multiple: The largest number before 200 that's divisible by 9 is 198. (200 / 9 = 22 with a remainder; 22 * 9 = 198).
- Calculating the Count: We can use the formula from the reference: (Last Multiple - First Multiple +9)/9 which is (198-108+9)/9 = 99/9=11. Alternatively, since the numbers are in an arithmetic progression, it can also be calculated using the formula
[(last number - first number)/ divisor] + 1 = [(198 - 108)/9] + 1 = [90/9] + 1 = 10 + 1 = 11
Listing the Multiples
To illustrate, the multiples of 9 between 101 and 200 are:
- 108
- 117
- 126
- 135
- 144
- 153
- 162
- 171
- 180
- 189
- 198
Therefore, there are 11 numbers between 101 and 200 that are divisible by 9.