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How to Find Ratios in Similar Triangles?

Published in Geometry 3 mins read

Finding ratios in similar triangles relies on the fundamental property that corresponding sides of similar triangles are proportional. This means the ratio between any two corresponding sides in one triangle will be equal to the ratio between the corresponding sides in the other triangle.

Here's a breakdown of how to find these ratios:

1. Understanding Similarity

  • Definition: Two triangles are similar if their corresponding angles are congruent (equal) and their corresponding sides are proportional.
  • Notation: We use the symbol ~ to denote similarity. For example, ΔABC ~ ΔDEF means triangle ABC is similar to triangle DEF.
  • Key Implication: If ΔABC ~ ΔDEF, then:
    • ∠A = ∠D
    • ∠B = ∠E
    • ∠C = ∠F
    • AB/DE = BC/EF = AC/DF

2. Identifying Corresponding Sides

This is a crucial step. Corresponding sides are the sides that are opposite congruent angles. Pay attention to the order in the similarity statement (e.g., ΔABC ~ ΔDEF):

  • AB corresponds to DE
  • BC corresponds to EF
  • AC corresponds to DF

3. Setting Up Proportions

Once you've identified the corresponding sides, you can set up proportions (equal ratios):

  • Basic Proportion: AB/DE = BC/EF = AC/DF
  • Example: Suppose in ΔABC, AB = 6, BC = 8, and AC = 10. In ΔDEF, DE = 3. If ΔABC ~ ΔDEF, we can find EF and DF.

4. Solving for Unknown Sides

Use cross-multiplication to solve for unknown side lengths in the proportions.

  • Continuing the example:
    • 6/3 = 8/EF => 6 EF = 3 8 => EF = 4
    • 6/3 = 10/DF => 6 DF = 3 10 => DF = 5

5. Area Ratios

The ratio of the areas of two similar triangles is the square of the ratio of their corresponding sides.

  • Area(ΔABC) / Area(ΔDEF) = (AB/DE)² = (BC/EF)² = (AC/DF)²
  • Example: If AB/DE = 2, then Area(ΔABC) / Area(ΔDEF) = 2² = 4. This means the area of ΔABC is four times the area of ΔDEF.

Example Problem:

Given ΔPQR ~ ΔXYZ, PQ = 4, QR = 6, PR = 8, and XY = 8. Find YZ and XZ.

  1. Set up proportions:
    PQ/XY = QR/YZ = PR/XZ
    4/8 = 6/YZ = 8/XZ
  2. Solve for YZ:
    4/8 = 6/YZ => 4 YZ = 8 6 => YZ = 12
  3. Solve for XZ:
    4/8 = 8/XZ => 4 XZ = 8 8 => XZ = 16

Summary:

To find ratios in similar triangles: identify corresponding sides, set up proportions based on those sides, and solve for any unknown values. Remember that the ratio of areas is the square of the ratio of corresponding sides.

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