There are exactly 11 two-digit numbers that are completely divisible by 8.
To determine how many two-digit numbers are divisible by 8, we can consider the following:
- The smallest two-digit number is 10.
- The largest two-digit number is 99.
We need to find the multiples of 8 that fall within this range. Let's examine a method to solve this:
- The first two-digit number divisible by 8 is 16 (8 * 2).
- We can find this by starting with 8, and find the multiples 8 * 1 = 8 (1 digit number) , then 8 * 2 = 16, which is the first 2 digit number divisible by 8.
- The largest two-digit number is 99. Dividing 99 by 8 gives us 12.375, so 8 * 12 = 96 is the last two digit number divisible by 8.
- We can list the multiples: 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, and 96
- We can determine the number of two-digit multiples of 8 by calculating (96 -16) / 8 +1 = 80 / 8 + 1 = 10 +1 = 11
Therefore, based on our calculations, there are 11 two-digit numbers that are divisible by 8. This aligns with the reference provided which stated: "The smallest 2 digit number is 10 and the highest is 99. The range of numbers is 99–10+1=90. Divide 90/8=11.25. Therefore, there are 11 two digit numbers that are divisible by 8."
