The answer is 112.
To determine the number of three-digit natural numbers divisible by 8, we need to identify the smallest and largest three-digit numbers that are multiples of 8, and then count all the multiples within that range.
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Smallest three-digit number divisible by 8: The smallest three-digit number is 100. Dividing 100 by 8 gives 12.5. So the smallest three-digit number divisible by 8 is 13 * 8 = 104.
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Largest three-digit number divisible by 8: The largest three-digit number is 999. Dividing 999 by 8 gives 124.875. So, the largest three-digit number divisible by 8 is 124 * 8 = 992.
Now, we have an arithmetic sequence with a first term of 104 and last term of 992, with common difference of 8.
To find the number of terms (or how many numbers) in this sequence, we can use the formula:
Number of terms = (Last term - First term)/ Common difference + 1
Number of terms = (992 - 104) / 8 + 1
Number of terms = 888 / 8 + 1
Number of terms = 111 + 1
Number of terms = 112
Therefore, there are 112 three-digit numbers that are divisible by 8, confirming the information provided in the reference.
