The question asks for the number of 5-digit numbers divisible by 5. A number is divisible by 5 if its last digit is either 0 or 5.
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Understanding the Constraints:
- A 5-digit number cannot start with 0.
- The last digit must be 0 or 5.
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Breaking down the problem:
We need to find the number of possibilities for each digit:
- First Digit: Can be any digit from 1 to 9. So, 9 possibilities.
- Second Digit: Can be any digit from 0 to 9. So, 10 possibilities.
- Third Digit: Can be any digit from 0 to 9. So, 10 possibilities.
- Fourth Digit: Can be any digit from 0 to 9. So, 10 possibilities.
- Fifth Digit: Must be either 0 or 5. So, 2 possibilities.
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Calculation:
Total number of 5-digit numbers divisible by 5 = 9 10 10 10 2 = 18,000.
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Referenced Information:
The provided text states "...total number of five digit numbers divisible by 5 is 120+96=216...". This information is not relevant to the general case of forming a five digit number divisible by 5, and appears to be specific to a limited set of digits.
Therefore, the total number of 5-digit numbers divisible by 5 is 18,000.
