Yes, all numbers divisible by 10 are also divisible by 5.
A number is divisible by 10 if it can be divided by 10 with no remainder. This means the number can be expressed as 10 k, where k is an integer. Since 10 can be factored into 2 5, we can rewrite the expression as (2 5) k, which can be rearranged as 5 (2 k). Because 2 k is also an integer, let's call it 'm'. Now we have 5 m, which clearly shows that the original number is also divisible by 5.
Here's why this holds true:
- Divisibility Rule for 10: A number is divisible by 10 if its last digit is 0.
- Divisibility Rule for 5: A number is divisible by 5 if its last digit is 0 or 5.
Therefore, if a number ends in 0 (and is divisible by 10), it also ends in 0 or 5 (and is divisible by 5).
Examples:
- 20 is divisible by 10 (20 / 10 = 2) and also divisible by 5 (20 / 5 = 4).
- 50 is divisible by 10 (50 / 10 = 5) and also divisible by 5 (50 / 5 = 10).
- 100 is divisible by 10 (100 / 10 = 10) and also divisible by 5 (100 / 5 = 20).
In conclusion, the statement is accurate because the divisibility rule of 10 inherently includes the divisibility rule of 5.
