There are 15 two-digit numbers divisible by 6.
These numbers form an arithmetic progression (AP) with the first term being 12 and the common difference being 6. The last two-digit number divisible by 6 is 96.
To find the number of terms in this AP, we can use the formula:
- a + (n - 1)d = l
where:
- a is the first term (12)
- n is the number of terms (unknown)
- d is the common difference (6)
- l is the last term (96)
Substituting these values into the formula:
- 12 + (n - 1)6 = 96
- 6n + 6 = 96
- 6n = 90
- n = 15
Therefore, there are 15 two-digit numbers divisible by 6.
