There are 15 two-digit numbers that are divisible by 6.
To determine this, we need to find the smallest and largest two-digit numbers divisible by 6.
- The smallest two-digit number is 10. Dividing 10 by 6 gives us 1 with a remainder of 4. Therefore, the smallest two-digit number divisible by 6 is 6 * 2 = 12.
- The largest two-digit number is 99. Dividing 99 by 6 gives us 16 with a remainder of 3. Therefore, the largest two-digit number divisible by 6 is 6 * 16 = 96.
So, we need to count the multiples of 6 from 12 (6 2) to 96 (6 16). This is the same as counting the integers from 2 to 16, inclusive.
To find the total number of multiples, we subtract the starting multiple (2) from the ending multiple (16) and add 1: 16 - 2 + 1 = 15.
Therefore, there are 15 two-digit numbers divisible by 6. These are: 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, and 96.
