What is a pair of negative integers whose difference gives 8?

A pair of negative integers whose difference is 8 can be, for example, -2 and -10.

Explanation

Let's denote the two negative integers as 'x' and 'y'. The question states that their difference is 8. This can be expressed as:

x - y = 8

We need to find values for x and y that satisfy this equation, where both x and y are negative integers.

Let's choose x = -2. Substituting this into the equation, we get:

-2 - y = 8

To solve for y, we can add 2 to both sides:

-y = 10

Then, multiply both sides by -1:

y = -10

So, the pair (-2, -10) satisfies the condition. Indeed, -2 - (-10) = -2 + 10 = 8.

Let's choose x = -4. Substituting this into the equation, we get:

-4 - y = 8

To solve for y, we can add 4 to both sides:

-y = 12

Then, multiply both sides by -1:

y = -12

So, the pair (-4, -12) satisfies the condition. Indeed, -4 - (-12) = -4 + 12 = 8.

Therefore, there are infinitely many possible solutions. Some examples include:

(-1, -9)
(-2, -10)
(-3, -11)
(-4, -12)
(-5, -13)
(-6, -14)