The sum of the first 100 integers is 5050.
This can be easily calculated using the formula for the sum of an arithmetic series. An arithmetic series is a sequence of numbers in which the difference between consecutive terms is constant. In this case, the series is 1 + 2 + 3 + ... + 100, where the first term (a) is 1, the last term (l) is 100, and the number of terms (n) is 100.
The formula for the sum (S) of an arithmetic series is:
S = (n/2) * (a + l)
Applying this formula to our problem:
S = (100/2) (1 + 100)
S = 50 101
S = 5050
Therefore, the sum of the first 100 integers is indeed 5050. We can also use the formula S = n(n+1)/2. In this case S = 100(100+1)/2 = 100(101)/2 = 10100/2 = 5050.
