The smallest 3-digit number exactly divisible by 3 is 102.
Here's how we determine that:
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Understanding Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3.
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Finding the Smallest 3-Digit Number: The smallest 3-digit number is 100.
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Checking Divisibility: The sum of digits in 100 is 1 + 0 + 0 = 1, which is not divisible by 3.
- 101 sums to 2, which isn't divisible by 3 either.
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Finding the Solution: Based on the provided reference, the first three digit number divisible by 3 is 102. We can confirm this by adding the digits: 1 + 0 + 2 = 3, which is divisible by 3.
Therefore, the smallest 3-digit number that is exactly divisible by 3 is 102.
