The odd integers between 1 and 2001 are: 1, 3, 5, 7, ..., 1997, 1999, 2001.
These numbers form an arithmetic progression with a common difference of 2. To determine how many odd integers are in this sequence, we can use the formula for the nth term of an arithmetic sequence:
an = a1 + (n - 1)d
where:
- an is the nth term (in this case, 2001)
- a1 is the first term (in this case, 1)
- n is the number of terms (what we want to find)
- d is the common difference (in this case, 2)
So, we have:
2001 = 1 + (n - 1)2
Solving for n:
2000 = (n - 1)2
1000 = n - 1
n = 1001
Therefore, there are 1001 odd integers between 1 and 2001, and the complete list is:
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, ..., 1983, 1985, 1987, 1989, 1991, 1993, 1995, 1997, 1999, 2001