There are 180 three-digit integers that are multiples of 5.
Understanding the Problem
The question asks for the number of three-digit integers (numbers between 100 and 999 inclusive) that are divisible by 5. A number is divisible by 5 if its last digit is either 0 or 5.
Solution
- Smallest Three-Digit Multiple of 5: The smallest three-digit number divisible by 5 is 100.
- Largest Three-Digit Multiple of 5: The largest three-digit number divisible by 5 is 995.
- Number of Multiples: To find the total number of multiples, we can use the formula:
(largest - smallest) / 5 + 1. This gives us (995 - 100) / 5 + 1 = 180.
Therefore, there are 180 three-digit integers that are multiples of 5. Note that while some references mention a different answer (e.g., 179 or 136), these appear to be incorrect based on a straightforward calculation.
Examples
- 100, 105, 110, 115... are all three-digit multiples of 5.
- 990, 995 are also three-digit multiples of 5.
