There are 180 three-digit numbers divisible by 5.
Understanding the Solution
This problem involves finding the number of three-digit integers that are multiples of 5. We can solve this using a simple arithmetic approach.
- Smallest three-digit number divisible by 5: 100
- Largest three-digit number divisible by 5: 995
These numbers form an arithmetic sequence with a common difference of 5. To find the number of terms in this sequence, we can use the formula:
Number of terms = (Largest number - Smallest number) / Common difference + 1
Substituting the values, we get:
Number of terms = (995 - 100) / 5 + 1 = 895 / 5 + 1 = 179 + 1 = 180
Therefore, there are 180 three-digit numbers divisible by 5. This aligns with the information found in various sources, including those referenced below which state that there are 180 such numbers.
References supporting this calculation:
- Several sources, including Testbook, corroborate the starting and ending points (100 and 995) of the sequence of three-digit numbers divisible by 5.
- The divisibility rule for 5, as stated in one reference, provides the foundation for this solution: a number is divisible by 5 if its last digit is 0 or 5.
