There are 11 two-digit numbers divisible by 8.
This can be solved in a few ways:
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Method 1: Listing and Counting: The two-digit numbers divisible by 8 are 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, and 96. Counting these gives us a total of 11 numbers.
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Method 2: Arithmetic Progression: The two-digit numbers divisible by 8 form an arithmetic progression (AP) with the first term (a) = 16, the common difference (d) = 8, and the last term (an) = 96. We can use the formula for the nth term of an AP: an = a + (n-1)d. Solving for n (the number of terms): 96 = 16 + (n-1)8 which simplifies to n = 11.
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Method 3: Division and Rounding: The smallest two-digit number is 10, and the largest is 99. Dividing the range of numbers (99-10+1 = 90) by 8 (90/8 = 11.25) and rounding down to the nearest whole number gives us 11. This method provides an approximation; however, in this instance, it gives the exact answer.
Multiple sources confirm this answer: Toppr, Quora, CK-12, Vedantu, and others.
