Synthetic division provides a streamlined way to find roots of a cubic polynomial and subsequently factor it. Here's how to use it:
1. Find a Potential Root Using the Rational Root Theorem:
- The Rational Root Theorem states that any rational root of the polynomial
ax³ + bx² + cx + d = 0
will be of the formp/q
, wherep
is a factor of the constant termd
, andq
is a factor of the leading coefficienta
. - List all possible rational roots (both positive and negative).
2. Set Up the Synthetic Division:
- Write the potential root you're testing (let's call it
r
) to the left, outside a division-like symbol. - Write the coefficients of the cubic polynomial (
a
,b
,c
, andd
) horizontally to the right of the division symbol. Make sure to include 0 for any missing terms.
3. Perform the Synthetic Division:
- Bring down the leading coefficient (
a
) to the bottom row. - Multiply the number you just brought down (
a
) by the potential root (r
). Write the result under the next coefficient (b
). - Add the numbers in that column (
b
and the result from step 2). Write the sum in the bottom row. - Repeat steps 2 and 3 for the remaining coefficients.
4. Interpret the Results:
- If the remainder (the last number in the bottom row) is 0, then the potential root
r
is a root of the polynomial. This means(x - r)
is a factor of the polynomial. - If the remainder is not 0, then
r
is not a root, and you should try a different potential root.
5. Write the Factored Form:
- If you found a root
r
, the numbers in the bottom row (excluding the last number, which is the remainder) are the coefficients of the quadratic factor. Specifically, if the bottom row containsa'
,b'
, andc'
, then the quadratic factor isa'x² + b'x + c'
. - The factored form of the cubic polynomial is then
(x - r)(a'x² + b'x + c')
.
6. Factor the Quadratic (if possible):
- The quadratic factor
a'x² + b'x + c'
can sometimes be factored further into two linear factors. You can use factoring techniques, the quadratic formula, or complete the square.
Example:
Factor the cubic polynomial x³ - 6x² + 11x - 6
.
- Rational Root Theorem: Possible rational roots are ±1, ±2, ±3, ±6.
- Test x = 1:
1 | 1 -6 11 -6
| 1 -5 6
|----------------
1 -5 6 0
- Interpretation: The remainder is 0, so x = 1 is a root. Therefore, (x - 1) is a factor. The quadratic factor is x² - 5x + 6.
- Write Factored Form: (x - 1)(x² - 5x + 6)
- Factor Quadratic: x² - 5x + 6 = (x - 2)(x - 3)
Therefore, the fully factored form is (x - 1)(x - 2)(x - 3)
.