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How to Factorise a Cubic Polynomial?

Published in Polynomial Factorization 2 mins read

To factorise a cubic polynomial, you can follow a step-by-step approach that involves finding a root and then performing division to obtain a quadratic factor.

Steps to Factorise a Cubic Polynomial

Here's a detailed breakdown of the steps involved in factorising a cubic polynomial, based on the reference provided:

Step Description
1 Find a Root: Identify a root, let's say 'a', of the cubic polynomial. This means that when 'a' is substituted into the polynomial, the result is zero. A potential root can often be found among the prime factors of the constant term of the polynomial. If f(a) = 0, then (x - a) is a factor.
2 Divide to Find Quadratic Factor: Divide the original cubic polynomial by the linear factor (x - a). The result of this division will be a quadratic polynomial.
3 Factorise Quadratic Factor: Factorise the quadratic polynomial obtained in the previous step. This can be done using techniques such as factoring by grouping, completing the square, or using the quadratic formula.

Example

Let's consider a simple example. Suppose you have the cubic polynomial:

f(x) = x3 - 6x2 + 11x - 6

Step 1: Find a Root

By trying factors of -6 (±1, ±2, ±3, ±6), we find that f(1) = 1 - 6 + 11 - 6 = 0. Therefore, x = 1 is a root, and (x - 1) is a factor.

Step 2: Divide to Find Quadratic Factor

Divide x3 - 6x2 + 11x - 6 by (x - 1). This can be done using polynomial long division or synthetic division. The result is x2 - 5x + 6.

Step 3: Factorise Quadratic Factor

Factorise the quadratic x2 - 5x + 6. This factors into (x - 2)(x - 3).

Therefore, the complete factorisation of the cubic polynomial is:

x3 - 6x2 + 11x - 6 = (x - 1)(x - 2)(x - 3)

Additional Considerations

  • Rational Root Theorem: The Rational Root Theorem can help narrow down the possible rational roots of the polynomial.
  • Synthetic Division: Synthetic division is a faster method for dividing by a linear factor.
  • Non-Factorable Quadratics: If the quadratic factor obtained is not factorable using real numbers, the cubic polynomial has only one real root and two complex roots.

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