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What is the First Derivative of a Quadratic Function?

Published in Quadratic Derivatives 2 mins read

The first derivative of a quadratic function f(x) = ax² + bx + c is f'(x) = 2ax + b.

Understanding the Derivative of a Quadratic Function

Let's break down why the derivative of a quadratic function takes this form.

Quadratic Function Form

A quadratic function is generally expressed as:

  • f(x) = ax² + bx + c

Where:

  • 'a', 'b', and 'c' are constants.
  • 'x' is the variable.

Applying the Power Rule of Differentiation

To find the derivative, we use the power rule of differentiation, which states:

  • If f(x) = xⁿ, then f'(x) = nxⁿ⁻¹

Applying this rule to each term in the quadratic function:

  1. Derivative of ax²:
    • Using the power rule: 2 * ax²⁻¹ = 2ax
  2. Derivative of bx:
    • This is equivalent to bx¹, so applying the power rule: 1 * bx¹⁻¹ = b
  3. Derivative of c:
    • The derivative of a constant is 0.

The Resulting First Derivative

Combining the derivatives of each term, we get:

  • f'(x) = 2ax + b + 0
  • f'(x) = 2ax + b

Practical Insights

  • Slope: The first derivative f'(x) of a quadratic function gives the slope of the tangent line to the curve at any given point x.
  • Linear Nature: As noted in the provided reference, the first derivative is a linear function (2ax + b). This is because the original quadratic function's degree is 2.
  • Finding Minimum/Maximum: The derivative is essential in finding the minimum or maximum value of a quadratic function. The point where the derivative equals zero represents the vertex of the parabola.

Example:

Let's take the quadratic function: f(x) = 3x² + 5x + 2
The derivative, based on our formula f'(x) = 2ax + b, would be f'(x) = 2(3)x + 5 = 6x + 5

Key Takeaway

The derivative of a quadratic function is always a linear function, a crucial piece of information for understanding its behavior. As mentioned in the reference, the discriminant (D = b² - 4ac) is a completely separate calculation and should not be confused with the first derivative (f'(x) = 2ax + b).

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