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How many solutions can a quadratic equation have in the real numbers?

Published in Quadratic Equations 2 mins read

A quadratic equation can have zero, one, or two real solutions.

A quadratic equation is a polynomial equation of degree two. It can be written in the general form:

ax2 + bx + c = 0

where a, b, and c are constants, and a ≠ 0. The solutions to this equation are also called its roots. The number of real solutions depends on the discriminant, which is given by:

Δ = b2 - 4ac

Here's how the discriminant determines the number of real solutions:

Discriminant (Δ) Number of Real Solutions Explanation Example
Δ > 0 Two distinct real solutions The equation has two different real numbers as solutions. x2 - 5x + 6 = 0 has solutions x=2, x=3
Δ = 0 One real solution (repeated) The equation has one real number as a solution (also called a repeated root). x2 - 4x + 4 = 0 has solution x=2
Δ < 0 Zero real solutions The equation has no real number solutions; both solutions are complex numbers. x2 + 1 = 0 has no real solutions

Examples:

  • Two Real Solutions: The quadratic equation x2 - 3x + 2 = 0 has two real solutions, x = 1 and x = 2. The discriminant is (-3)2 - 4(1)(2) = 9 - 8 = 1 > 0.

  • One Real Solution: The quadratic equation x2 - 4x + 4 = 0 has one real solution, x = 2. The discriminant is (-4)2 - 4(1)(4) = 16 - 16 = 0.

  • Zero Real Solutions: The quadratic equation x2 + x + 1 = 0 has no real solutions. The discriminant is (1)2 - 4(1)(1) = 1 - 4 = -3 < 0. The solutions are complex numbers.

In summary, a quadratic equation can have 0, 1, or 2 real solutions, determined by the value of its discriminant.

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