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How do you find the vertex of a quadratic function in factored form?

Published in Quadratic Functions 2 mins read

The vertex of a quadratic function in factored form, f(x) = a(x - r₁)(x - r₂), is found by first determining the x-coordinate of the vertex (axis of symmetry) as the midpoint between the roots r₁ and r₂, and then substituting this x-value back into the function to find the y-coordinate.

Here's a step-by-step breakdown:

  1. Identify the Roots (x-intercepts): The factored form immediately gives you the roots of the quadratic equation. These are the values of x that make f(x) = 0. The roots are r₁ and r₂, found by setting each factor (x - r₁) and (x - r₂) to zero and solving for x.

    • x - r₁ = 0 => x = r₁
    • x - r₂ = 0 => x = r₂
  2. Calculate the x-coordinate of the Vertex (Axis of Symmetry): The x-coordinate of the vertex lies exactly in the middle of the two roots due to the parabola's symmetry. Calculate it using the midpoint formula:

    • x_vertex = (r₁ + r₂) / 2
  3. Calculate the y-coordinate of the Vertex: Substitute the x-coordinate of the vertex (x_vertex) back into the original factored form of the quadratic function to find the corresponding y-coordinate (y_vertex):

    • y_vertex = a(x_vertex - r₁)(x_vertex - r₂)
  4. Write the Vertex: The vertex is the point (x_vertex, y_vertex).

Example:

Consider the quadratic function f(x) = 2(x - 1)(x - 5).

  1. Roots: The roots are r₁ = 1 and r₂ = 5.

  2. x-coordinate of Vertex: x_vertex = (1 + 5) / 2 = 3

  3. y-coordinate of Vertex: y_vertex = 2(3 - 1)(3 - 5) = 2(2)(-2) = -8

  4. Vertex: The vertex is (3, -8).

In summary, finding the vertex from the factored form relies on the symmetry of the parabola. By averaging the roots, you find the x-value of the vertex, and then plugging this value back into the function provides the y-value.

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