To find the y-intercept of a quadratic function in vertex form, substitute x = 0
into the equation and solve for y
.
Here's a breakdown of the process:
-
Understand Vertex Form: The vertex form of a quadratic equation is given by:
y = a(x - h)^2 + k
where:
(h, k)
represents the vertex of the parabola.a
determines the direction and "width" of the parabola.
-
Substitute x = 0: To find the y-intercept, we need to find the value of
y
whenx
is zero. So, replacex
with0
in the equation:y = a(0 - h)^2 + k
-
Simplify and Solve for y: Simplify the equation and solve for
y
. This will give you the y-coordinate of the y-intercept. The y-intercept is the point(0, y)
.
Example:
Let's say you have the quadratic function in vertex form:
y = 2(x - 1)^2 + 3
-
Substitute
x = 0
:y = 2(0 - 1)^2 + 3
-
Simplify:
y = 2(-1)^2 + 3
y = 2(1) + 3
y = 2 + 3
y = 5
Therefore, the y-intercept is (0, 5)
.
In summary, the key is to replace x
with zero in the vertex form equation and then isolate and solve for y
. The resulting y
value gives you the y-coordinate of the y-intercept.