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What is a Symmetric Function of the Roots of a Quadratic Equation?

Published in Quadratic Roots Functions 3 mins read

A symmetric function of the roots of a quadratic equation is a function that doesn't change its value when the roots are interchanged. In simpler terms, it's an expression involving the roots of the quadratic equation that remains the same regardless of how you swap the roots.

Understanding Symmetric Functions

The core concept is symmetry with respect to the roots. Let's say you have a quadratic equation and its roots are x1 and x2.

  • Definition: If a function f(x1, x2) satisfies f(x1, x2) = f(x2, x1), then f is a symmetric function.

According to the provided reference: "If the function using the roots of the quadratic f(x1,x2) doesn't change on interchanging x1 and x2, then the function (f) is symmetric. In other words, an expression in x1 and x2, which remains the same when x1 and x2 are interchanged, is called a symmetric function in x1 and x2."

Examples of Symmetric Functions

Common examples of symmetric functions related to the roots x1 and x2 of a quadratic equation include:

  • Sum of the roots: x1 + x2
  • Product of the roots: x1x2
  • x12 + x22
  • (x1 + x2)2

Why are these symmetric? Because if you swap x1 and x2 in any of these expressions, the expression's value remains the same. For instance, x2 + x1 is the same as x1 + x2.

Importance of Symmetric Functions

Symmetric functions are significant because they can be expressed in terms of the coefficients of the quadratic equation. Consider a quadratic equation in the form ax2 + bx + c = 0. Vieta's formulas relate the coefficients of the polynomial to sums and products of its roots:

  • Sum of roots: x1 + x2 = -b/a
  • Product of roots: x1x2 = c/a

Therefore, any symmetric function of the roots can ultimately be written in terms of a, b, and c. This makes it possible to determine the value of symmetric expressions without actually finding the roots themselves.

Example Application

Suppose we want to find the value of x12 + x22 for the quadratic equation x2 - 5x + 6 = 0.

We know:

  • x1 + x2 = 5
  • x1x2 = 6

We can rewrite x12 + x22 as follows:

x12 + x22 = (x1 + x2)2 - 2x1x2

Substituting the values, we get:

x12 + x22 = (5)2 - 2(6) = 25 - 12 = 13

Thus, the value of x12 + x22 is 13, and we found this without explicitly calculating x1 and x2.

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