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How to Find the nth Term of a Quadratic Sequence?

Published in Quadratic Sequences 3 mins read

To find the nth term of a quadratic sequence, you can use a general formula and a simple method involving the differences between terms. Here's how:

Understanding Quadratic Sequences

A quadratic sequence is a sequence of numbers where the second differences between consecutive terms are constant. The general formula for a quadratic sequence's nth term is:

Tn = an2 + bn + c

Where:

  • Tn is the nth term of the sequence.
  • n is the position of the term in the sequence (1st, 2nd, 3rd, etc.).
  • a, b, and c are constants that need to be determined.

Method to Find a, b, and c

  1. Calculate the First Differences: Find the differences between consecutive terms of the sequence.
  2. Calculate the Second Differences: Find the differences between the first differences. If these are constant, the sequence is quadratic.
  3. Determine 'a': According to the reference, "a is a half of the second difference." In other words:
    a = (Second Difference) / 2
  4. Construct a New Sequence: Subtract an2 from each term of the original sequence.
  5. Find b and c: The new sequence should be a linear sequence, where the difference between each term is now a constant value. Use the method to find the nth term for linear sequences, which is dn + e, where d represents the difference, and e is the zero term (the term before the first term in the linear sequence).
    • b is equal to d and c is equal to e.
  6. Write the nth term: Substitute the values of a, b, and c into the general formula: Tn = an2 + bn + c

Example

Let's find the nth term of the quadratic sequence: 3, 10, 21, 36...

Sequence (Tn) 3 10 21 36
1st Differences 7 11 15
2nd Differences 4 4
  • a: (Second difference)/2 = 4/2 = 2
  • an2 = 2n2.
  • Subtract 2n2 from the original terms.
    • n = 1 : 3 - (2 * 12) = 1
    • n = 2 : 10 - (2 * 22) = 2
    • n = 3 : 21 - (2 * 32) = 3
    • n = 4 : 36 - (2 * 42) = 4
  • New Sequence is now: 1, 2, 3, 4…

This shows the new sequence has a constant difference of 1 (d) and the zero term (e) is 0 so, the nth term is: 1n + 0, which means b = 1 and c = 0

Therefore, the nth term of the original sequence is :
Tn = 2n2 + 1n + 0

Which simplifies to
Tn = 2n2 + n

Summary

To find the nth term of a quadratic sequence:

  • Identify the first and second differences.
  • Calculate 'a' as half the second difference.
  • Subtract an2 from the original sequence terms.
  • Determine the nth term of the resulting linear sequence, which gives 'b' and 'c'.
  • Substitute 'a', 'b', and 'c' into the quadratic formula an2 + bn + c.

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