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How to find equivalent weight in redox reactions?

Published in Redox Chemistry 3 mins read

The equivalent weight in redox reactions is determined by considering the molecular weight of a substance and the number of electrons involved in the reaction.

Understanding Equivalent Weight in Redox Reactions

In redox reactions, where oxidation and reduction processes occur, the concept of equivalent weight is crucial for understanding the quantitative relationships between reactants. Unlike acid-base reactions, where equivalent weight is based on the number of replaceable hydrogen or hydroxyl ions, in redox reactions, it's based on the number of electrons gained or lost.

Key Concepts

  • Redox Reactions: Chemical reactions involving the transfer of electrons.
  • Oxidation: Loss of electrons.
  • Reduction: Gain of electrons.
  • Oxidizing Agent: A substance that gains electrons and gets reduced.
  • Reducing Agent: A substance that loses electrons and gets oxidized.

Calculating Equivalent Weight

According to the reference, the equivalent weight of a substance (whether an oxidant or a reductant) is determined by:

Equivalent Weight = (Molecular Weight) / (Number of electrons lost or gained per molecule)


This simple formula encapsulates the core concept of equivalent weight in redox chemistry.

Steps to Calculate Equivalent Weight in Redox Reactions

  1. Determine the Balanced Redox Reaction: Write and balance the redox reaction, identifying the oxidizing and reducing agents.
  2. Identify the Change in Oxidation Number: Determine how many electrons each molecule of the reactant loses or gains. This change corresponds to the change in oxidation number of the element that is undergoing redox.
  3. Calculate the Molecular Weight: Calculate the molecular weight of the substance.
  4. Apply the Formula: Divide the molecular weight by the number of electrons transferred per molecule.

Example

Consider the reduction of potassium permanganate (KMnO4) in acidic medium:
MnO4- + 8H+ + 5e- → Mn2+ + 4H2O

In this case, one MnO4- gains 5 electrons.

  • If we know that the molar mass of KMnO4 is approximately 158 g/mol,
  • Then the equivalent weight of KMnO4 in this reaction is 158 g/mol / 5 = 31.6 g/equiv.

Practical Insights and Solutions

  • Importance of Balancing: Correctly balancing the redox equation is essential to find the correct number of electrons transferred.
  • Context Matters: Equivalent weight is specific to a particular redox reaction. The same substance may have different equivalent weights in different reactions, depending on the number of electrons transferred per molecule.
  • Normality Calculations: Equivalent weight is directly used in normality calculations for redox titrations, allowing you to accurately determine concentrations of solutions used in redox reactions.
  • Stoichiometric Ratios: Equivalent weights help establish stoichiometric relationships between reactants in redox reactions.
  • Conceptual Understanding: Understanding that equivalent weight relates to the amount of substance that will react with or supply a defined number of moles of electrons, which also aligns with practical uses.

Conclusion

Calculating the equivalent weight in redox reactions is essential for quantitative analysis. By dividing the molecular weight of a substance by the number of electrons transferred during the reaction, you can accurately determine how much of the substance is required for a specific reaction or how much product will be produced.

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