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How do you find reduced mass in chemistry?

Published in Reduced Mass Calculation 3 mins read

Reduced mass in chemistry is a concept used to simplify calculations for systems involving two or more bodies, particularly in molecular vibrations and rotations. It allows us to treat a two-body problem as a single-body problem with the reduced mass. The formula to calculate reduced mass depends on the system and its arrangement, especially linear configurations.

Reduced Mass for Different Molecular Arrangements

The calculation of reduced mass differs depending on the molecular arrangement. Here's a detailed breakdown based on the provided references:

Simple Diatomic Molecule

For a simple diatomic molecule (two atoms), the reduced mass (μ) is calculated using the following formula:

μ = (m₁ * m₂) / (m₁ + m₂)

Where:

  • m₁ is the mass of the first atom.
  • m₂ is the mass of the second atom.

Linear Triatomic Molecule

For a linear molecule with three atoms, such as HCN, the reduced mass (M) is calculated with this formula:

M = (m₁m₂ + m₂m₃ + m₁m₃) / (m₁ + m₂ + m₃)

Where:

  • m₁, m₂, and m₃ are the masses of the respective atoms.

Linear Polyatomic Molecule

For a linear molecule with four atoms or more, such as O=C=N-Cl, the reduced mass (M) formula expands further:

M = (m₁m₂m₃ + m₁m₂m₄ + m₂m₃m₄ + m₁m₃m₄) / (m₁m₂ + m₁m₃ + m₁m₄ + m₂m₃ + m₂m₄ + m₃m₄)

Where:

  • m₁, m₂, m₃ and m₄ are the masses of the respective atoms.

Summary of Reduced Mass Formulas

Molecule Type Formula
Diatomic μ = (m₁ * m₂) / (m₁ + m₂)
Linear Triatomic M = (m₁m₂ + m₂m₃ + m₁m₃) / (m₁ + m₂ + m₃)
Linear Polyatomic M = (m₁m₂m₃ + m₁m₂m₄ + m₂m₃m₄ + m₁m₃m₄) / (m₁m₂ + m₁m₃ + m₁m₄ + m₂m₃ + m₂m₄ + m₃m₄)

Practical Insight: The reduced mass is always smaller than the mass of any individual atom in the system. It represents the effective mass of the system when calculating its dynamic properties.

Example
Let's calculate the reduced mass for the linear triatomic molecule HCN, assuming the mass of Hydrogen = 1, Carbon= 12, and Nitrogen = 14.

M = (1 12 + 12 14 + 1 * 14) / (1 + 12 + 14)
M = (12 + 168 + 14) / 27
M = 194 / 27
M ≈ 7.19 amu.

Conclusion

Calculating reduced mass allows for simplified analysis of complex systems, particularly when analyzing molecular vibrations, rotations, and reactions. It is an essential tool in physical chemistry.

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